PLEASE HELP:How to find A square when B square =4 and C square =4 ^root 5 using the pythagoran formula?

I have to assume that your basis is C^2 = A^2+B^2


or A^2 =C^2-B^2


A^2 = 16*5-16 = 80-16 = 64


A = 8


Check: A^2+B^2 = 64+16 = sqrt(80) = sqrt(16*5) = 4*sqrt(5)





(Key is [4*sqrt(5)]squared = 16*5)

PLEASE HELP:How to find A square when B square =4 and C square =4 ^root 5 using the pythagoran formula?
Please double check to make sure you are stating the problem correctly.





But if you are then:





A^2 = C^2 -B^2





= 4 sqrt 5 -4 = 4 (sqrt5 -1)