the equation is f(x)=25–x^2 [0,1]
I already found what the average value of the function is, its 24.66 but I can't find C
Find a value c in the interval [0,1] such that f(c) is equal to the average value?
24.66 = 25-x^2
x^2 = 0.34
x = sqrt 0.34 = 0.58
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