Friday, July 31, 2009

Does anyone know how to work out this equation to find the nth term a+(n-1)d+1/2(n-1)(n-2)C?

I'm revising form mymaths g.c.se.and i came across this formula i know how to multiply out the frst part but i don't kno whow to multiply out the second half 1/2(n-1)(n-2)C please help i'm really stuck i've looked in my revision guide and on the internet but still can't find anything.

Does anyone know how to work out this equation to find the nth term a+(n-1)d+1/2(n-1)(n-2)C?
Your title says, "Does anyone know how to work out this equation...", its not an equation if there is no '=' sign.





To find the n'th term, you need a sequence or series, you have just given an expression containing 3 terms.


If you want to multiply out 1/2(n-1)(n-2)C you can write this as C/2(n-1)(n-2).


Then expanding brackets.. C/2(n^2-3n+2) and expand again if you want... (Cn^2)/2-3Cn/2+C.





That help?
Reply:I could be completley wrong here but is it anything to do with two minuses giving you a positive.....


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