i am not grasping the concept of oxidation numbers.. at all , help would be much appreciated thank you
How would i find the oxidation number of C in CO, CO2, CH2O, CH4O, C2H6O, and Na2CO3?
The sum of oxidation no. of all atoms = the overall charge of the molecule.
O.S of O= -2
O.S of H= +1
O.S of Na= +1 (since it's existing as Na+1)
let x be O.S of C in C2H6O