Find the F and C intercepts of the line described in this equation?

To change the temprature from degrees Fahrenheit to degrees celsius, use formula:


c=5/9(F-32).





I need to find the F and C intercepts. I would like someone to show me how to do this.





Thanks a bunch :)


Cristy

Find the F and C intercepts of the line described in this equation?
1. Find the "C" intercept. First: replace "0" with the "F" variable %26gt;





C = 5/9(0 - 32)





Sec: multiply the numerators %26gt;





C = (5/9)(-32)


C = -160/9





2. Find the "F" intercept. First: replace "0" with the "C" variable %26gt;





0 = 5/9(F - 32)





Sec: use distribution %26gt; multiply 5/9 with both terms in the parenthesis %26gt;





0 = (5/9)F - (5/9)(32)


0 = (5/9)F - 160/9





Third: eliminate fractions %26gt; multiply the denominator by everything and cancel "like" terms %26gt;





9(0) = (9)(5/9)F - 9(160/9)


0 = 5F - 160





*Add 160 to both sides %26gt;





0 + 160 = 5F - 160 + 160


160 = 5F





*Solve for "F" by isolating it %26gt; divide both sides by 5 %26gt;





160/5 = 5F/5


32 = F


F = 32
Reply:c=5/9(f-32)


to find the f intercept, set c=0


0=5/9 (f-32) divide by 5/9


0=f-32 add 32 to each side


f=32





to find the c intercept set f=0


c=5/9(0-32)=-5*32/9=-160/9=-17.77....
Reply:At c = 0, you get F-intercept = 32.


At F = 0, you get c-intercept = -160/9





F = 9c/5 + 32
Reply:to find the intercepts you just set the other variable to zero





i.e. to find the F intercept, set c=0 then solve for F





0=5/9(F-32) --%26gt; 9/5=(F-32) -----%26gt; F=(9/5)+32 ---%26gt;


F=169/5 or about 33.8





just do the same for c
Reply:The F and C intercepts are just like the x and y intercepts.





The C-intercept is the value of C where F = 0:





C = 5/9(0 - 32) = -160/9 = -17 7/9 degrees Celsius.





The F-intercept is the value of F where C = 0:





0 = 5/9(F - 32)





Multiply both sides by 9/5:





0 = F - 32


F = 32 degrees Fahrenheit (of course!)
Reply:When F=0, C = (5/9)(-32) = -17 7/9





When C = 0,


0 = (5/9)(F-32)


0 = F - 32


32 = F ....... by definition, in F system water freezes at 32, in C system, at 0.
Reply:for F intercept putC=0


0=(5/9)(F-32)


multiplying by (9/5)


0=F-32


adding 32


F=32





for C intercept put F=0


C=(5/9)(-32)


C=-160/9
Reply:I think you want to find the temperature at which F is equal to C so just set C = F and solve the equation F = 5/9(F -32) this will give the temperature at which they are equal. I will give you a hint. It is very cold.
Reply:c=5/9(f-32) *9


9c=5(f-32)


9c=5f-160 by arrange the equation


5f-9c=160 /160


f/32+c/(-160/9)=1


then f_intercept is 32 %26amp;c_intercept is -160/9