C(0,-4)
line: 2y - 5x = 4
Please show the steps clearly...I am still confused on how to find perpendicular distances...
thanks for your help!!
How to find the perpendicular distance from point C(0,-4) to the line with an equation 2y - 5x = 4?
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Perpendicular is the negative recipricol slope.
+5/2 becomes -2/5
y+4 = -2/5(x)
which crosses at the common point of intersection.
5Y + 20 = -2x
5y + 2x = 20 and 2y - 5x =4 .... solve simultaneously.
times first by 5 and second by 2 then add together
29Y = 108 ..... y = 108/29
First by two and second by -5 ....
29X = 20 .... x = 29/20.
So the other point is (108/29,29/20) and then find the distance to (0,-4). Use pyth formula.
Reply:2y - 5x = 4
y=5/2 x+2
in this equation 5/2 is slope of straigt line
slope of normala on y=5/2 x+2 is
-2/5
then
y=-2/5x+k is equation of perpendicular on y=5/2 x+2
if pass by C(0,-4) then
-4=k
then obtain
y=-2/5 x-4
y=5/2x +4
then x(5/2+2/5)=-8
x=-8*10/29
find y
And now you have intersect from 2y-5x=4 and
y=-2/5 x-4
distance from C(0,-4) and this point is
sqrt((0-x)^2+(-4-y)^2)
where x,y are coordonate of intersection
Reply:Given: C(0,-4) and line: 2y - 5x = 4 or 5x - 2y + 4
From analytical geometry:
d = |Ax1 + By1 + C|/√(A^2 + B^2)
where x1 = 0, y1 = -4
A = 2, B = -5, and C = 4
Substitute the values in the above formula for distance between a point and a line:
d = |(2)(0) + (-5)((-4) + 4|/√[(2^2 + (-5)^2]
d = 4.46 ANSWER
Hope I help you.
teddy boy
Reply:us the qudratic formula -b+/-(rootb^2-4ac)/2a then multiply by the diffirentiate the commen difference, Leaving you with the fact that you have no friends and will probably die a virgin.
(sorry that was a bad joke) If you need any tips i would go to www.mudfall.com - it realy helped me understand perpendicular distances - and its pretty easy to follow.
Reply:first write the equation like this--
5x-2y+4=0
now , put x=0 and y= -4 and divide it by sqrt of ( sqaure of 5 + square of 2)
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