How to find equation for (4,1) gradient: 5 anser has to be expressed in both ax+by+c=0 and y=mx+c?

i also need to know how to convert a y=mx+c equation to a ax+by+c=0 equation

How to find equation for (4,1) gradient: 5 anser has to be expressed in both ax+by+c=0 and y=mx+c?
y=mx+b





x=4, y=1 m=5





substitute that into y=mx+b or y=mx+c, where c/b is the y intercept





1=5*4+b


1=20+b


-20


-19=b


so the slope intercept form is





y=5x+-19


y=5x-19











MORE TO COME . . .





ax+by+c=0 is the general form equation for a straight line.


a,b,c are just numbers.


x is the x value and y is the y value.





You can change the slope intercept form the the general form, as long as you get the 0= part.





You can do this by usually minusing y from both sides.





y=5x-19


-y -y


0=5x-y-19





Just make sure you rearrange the equation so that c(a value) follows y and a value which follows x and another value.