Find teh illegal values of c in the multiplication statement?

(c^2-3c-10/2^2+5c-14) x (c^2-c-2/c^2-2c-15)

Find teh illegal values of c in the multiplication statement?
Sam is wrong -- there *are* illegal values of c. His basic principle is close. In this case, you need to avoid dividing by zero. To find the proper values, you need to set each denominator to zero, and solve for c. Any solutions you get are forbidden values.





The first denominator is linear, so I expect you can knock off that one in under two minutes. The second is quadratic, but factors easily enough (ab = -15; a+b = -2), so I'll leave that to you as well.
Reply:c cannot equal a zebra. i've looked into it and its JUST not possible...