Let f(x) = ax^2+ bx+ c be a quadratic function, where a, b, c, are parameters.
Given the specific values of a and b in (a) and c= -1, find the zero(s) of the function?
Is your question:
f(x) = ax^2 + bx - 1 ------where are the zeroes?
quadratic formula = (-b +/- sqrt(b^2 - 4ac)) / 2a
plug in values for a, b %26amp; c to find the zeroes. (I don't know what a %26amp; b are, but plugging in -1 for c:
(-b +/- sqrt(b^2 + 4a)) / 2a
Reply:I presume what we are saying is:
find the zero's of f(x) = ax^2 + bx - 1
By the quadratic formula:
x = (-b +/- sqrt(b^2 - 4(-1)(a))) / ( 2a)
= (-b +/- sqrt(b^2 + 4a))/(2a)
Reply:delta=b^2-4ac
delta=b^2-4a(-1)
delta=b^2+4a
x1=-b+sqrt(b^2+4a)/2a
x2=-b-sqrt(b^2+4a/2a
Does this answer your question?
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