Find the value of a, b, and c such that f(x) = ax3 + bx2 +cx has a minimum point at (1,-7) and a maximum point at (-2,20).
Find the value of a, b, and c such that f(x) = ax3 + bx2 +cx see details?
f ' (x)= 3ax^2+2bx+c
if (1,-7) is minimum point then
f ' (1)=0
and
f(1)=-7
f'(1)=3a+2b+c=0
a+b+c=-7
idem for (-2,20)
f'(-2)=12a+4b-c=0
f(-2)=-8a+4b-2c=20
you have a system of equation solve it and compute a,b,c.
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